Question

Bohr model of hydrogen is modified to be applied to other one-electron atoms/ions as = ― 2 2 where z is atomic number of the element also known as nuclear charge of the atom. using the bohr model, determine the energy in joules of the photon produced when an electron in a he ion moves from the orbit with n = 5 to the orbit with n = 2.

Answer 1

The energy of the photon produced when an electron in a Li²+ ion moves from the orbit with n = 2 to the orbit with n = 1 is -8.716 × 10^-18 J.

Step-by-step explanation:

According to the Bohr model, the energy of an electron in a hydrogen-like atom/ion can be calculated using the formula E = -2.179 × 10-18 * (Z2 / n2), where E is the energy, Z is the atomic number (nuclear charge), and n is the principal quantum number representing the orbit.

In this case, we are considering a Li²+ ion, which has a charge of +2. The electron is moving from the orbit with n = 2 to the orbit with n = 1. Plugging these values into the formula, we get:

E = -2.179 × 10-18 * (22 / 12)

E = -8.716 × 10-18 J

Therefore, the energy of the photon produced when the electron in a Li²+ ion moves from the orbit with n = 2 to the orbit with n = 1 is -8.716 × 10-18 J.