Final answer:
The throttling process of an ideal gas from 2500 kPa to 150 kPa adiabatically involves no work done (WG=0), and the entropy change cannot be calculated with the given information without additional thermodynamic relations or data.
Step-by-step explanation:
The question presented involves a thermodynamic process known as a throttling process, in which an ideal gas is expanded from a high pressure to a low pressure without any exchange of heat with its surroundings (adiabatic process). The student is asking for the entropy change (S) and the work done by the gas (WG) in the process, with the given steady-state flow rate of the gas and a source temperature (Ts).
It is important to note that during a throttling process, there is no work done (W=0) because the gas is expanding without doing work on a piston or similar mechanical system. Additionally, in an ideal throttling process, the enthalpy remains constant (h1=h2), and because there is no heat exchange, the entropy change for an ideal gas can be calculated using the relationship involving temperatures and pressures of the initial and final states.
However, the change in entropy (S) is not provided directly in the question and cannot be calculated solely from the provided information. To find the change in entropy, one would typically need to use a formula that relates entropy change to temperature and pressure for an ideal gas. The change in entropy for an ideal gas undergoing a throttling process is typically calculated using the relation ΔS = nRln(P2/P1) assuming constant specific heats.