Question

An object weighing 40 N rests on a surface. The coefficient of friction between the surface and the object is 0.35. What is the frictional force between the object and the surface? A 20 N force is applied to pull the object horizontally. What is the magnitude of the unbalanced force? What is the acceleration of the box?

Answer 1

The frictional force between the object and the surface is 14 N. The magnitude of the unbalanced force is 6 N, and the acceleration of the box is 0.15 m/s².

Step-by-step explanation:

To find the frictional force between the object and the surface, we can use the equation: frictional force = coefficient of friction × normal force. In this case, the normal force is equal to the weight of the object, which is 40 N. So, the frictional force is frictional force = 0.35 × 40 N = 14 N.

To find the magnitude of the unbalanced force, we need to subtract the frictional force from the applied force. The applied force is 20 N, so the unbalanced force is unbalanced force = 20 N - 14 N = 6 N.

The acceleration of the box can be found using Newton's second law of motion, which states that force = mass × acceleration. Rearranging the equation, we get acceleration = force / mass. Substituting the values, we have acceleration = 6 N / 40 kg = 0.15 m/s².