Question

A student used 35.0 g of NaOH to make a 0.25 m solution. What volume (in liters) of water did the student use to make this 0.25 m NaOH solution?

Answer 1

To prepare a 0.25 m NaOH solution with 35.0 g of NaOH, the student used 3.5 liters of water, calculated by dividing the moles of NaOH (0.875 moles) by the desired molarity (0.25 M).

Step-by-step explanation:

The volume of water needed to make a 0.25 m NaOH solution using 35.0 g of NaOH can be calculated using the formula molarity (M) = moles of solute / volume of solution in liters (L). First, we need to find the moles of NaOH, which is done by dividing the mass of NaOH by its molar mass. The molar mass of NaOH is 40.00 g/mol. Therefore, moles of NaOH = 35.0 g / 40.00 g/mol = 0.875 moles. Next, we use the molarity equation:

Molarity = moles of solute / volume of solution in liters

0.25 M = 0.875 moles / volume in liters

Volume in liters = 0.875 moles / 0.25 M = 3.5 liters

Therefore, the student used 3.5 liters of water to make the 0.25 m NaOH solution.