Question

An object is falling on earth (acceleration is 9.8 m/s²) initially moving 2 m/s. if the object falls for 4 seconds, how far did the object fall?

Answer 1

The object falls a distance of 86.4 meters.

Step-by-step explanation:

The distance an object falls can be calculated using the equation:

d = ut + 1/2gt^2

where d is the distance, u is the initial velocity, g is the acceleration due to gravity, and t is the time.

In this case, the initial velocity is 2 m/s, the acceleration is 9.8 m/s², and the time is 4 seconds. Plugging in these values, we have:

d = 2(4) + 1/2(9.8)(4)^2 = 8 + 1/2(9.8)(16) = 8 + 78.4 = 86.4 meters.

Therefore, the object falls a distance of 86.4 meters.