1.0k views
0 votes
A student conducts the following reaction. Fe₃O₄ + 4CO -> 3Fe + 4CO₂. If the student starts with 57.9 g CO, what is the percent tield of the reaction if only 42.8 grams of Fe were produced?

1 Answer

5 votes

Final answer:

To find the percent yield of the reaction, we need to compare the actual yield of Fe (42.8 g) to the theoretical yield of Fe (calculated from the balanced equation).

Step-by-step explanation:

To find the percent yield of the reaction, we need to compare the actual yield of Fe (42.8 g) to the theoretical yield of Fe (calculated from the balanced equation). We can calculate the theoretical yield of Fe using the stoichiometry of the balanced equation:

Fe₃O₄ + 4CO -> 3Fe + 4CO₂

From the equation, the molar ratio between CO and Fe is 4:3. We can convert the mass of CO (57.9 g) to moles using its molar mass, then use the mole ratio to calculate the moles of Fe. Finally, we can convert the moles of Fe to grams using its molar mass to find the theoretical yield.

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100%:

Percent Yield = (Actual Yield / Theoretical Yield) * 100%

Using the given values, we can substitute them into the formula to find the percent yield.

User Fred Bricon
by
8.1k points