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A projectile is fired with an initial velocity of 120 meter sper second at angle theta above the horizontal. if the projectiles horizontal speed is 55 meters per second, then theta's angle measure is

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Final answer:

To find the angle theta, we can use the equation for horizontal speed, which is given by: horizontal speed = initial velocity * cos(theta). Given that the horizontal speed is 55 m/s and the initial velocity is 120 m/s, we can solve for cos(theta).

Step-by-step explanation:

To find the angle theta, we can use the equation for horizontal speed, which is given by:

horizontal speed = initial velocity * cos(theta)

Given that the horizontal speed is 55 m/s and the initial velocity is 120 m/s, we can solve for cos(theta). Dividing both sides of the equation by the initial velocity, we get:

cos(theta) = horizontal speed / initial velocity = 55 / 120

Using a calculator, we can find the value of cos(theta) to be approximately 0.458. Taking the inverse cosine of this value, we can find theta to be approximately 63.43 degrees.

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