Final answer:
To calculate the skydiver's initial horizontal velocity, we would need the time of flight, which is not provided in the question. Without this information, it is not possible to determine the skydiver's initial speed.
Step-by-step explanation:
To determine how fast the skydiver was initially moving horizontally, we can use kinematics equations from physics, specifically those related to projectile motion.
The initial vertical velocity will be zero since the skydiver is jumping out of a plane, but there will be an initial horizontal velocity.
Since only the horizontal information is provided, we'll focus on that.
Horizontal motion is uniform, meaning that the horizontal speed (vx) remains constant since there is no horizontal acceleration in projectile motion (ignoring air resistance for simplicity).
Therefore, we can use the formula for horizontal displacement:
Horizontal displacement = Horizontal velocity (vx) × Time
To find the time (t), we need to solve for the time it takes to fall from 330 m vertically.
However, the question does not provide enough data to calculate the initial horizontal velocity because the time of flight is missing.
This time would be calculated using the vertical motion equations under gravity, but with no time or initial vertical velocity provided, we cannot provide an answer to the skydiver's initial horizontal velocity.