Final answer:
The frequency of electromagnetic radiation in this case is 9,192,631,770 Hz. The wavelength is approximately 3.261 nanometers.
Step-by-step explanation:
The frequency of electromagnetic radiation is determined by the number of times a wave passes a given point per second. In this case, the cesium-133 atom undergoes a specific transition 9,192,631,770 times in one second, which defines the duration of a second. Therefore, the frequency of this electromagnetic radiation is 9,192,631,770 Hz or cycles per second.
Using the equation for the speed of a wave, which is the product of the wavelength and the frequency, we can find the wavelength. The speed of light is approximately 2.998 × 10^8 m/s. Rearranging the equation, we have wavelength (λ) = speed of light (c) / frequency (f). Plugging in the frequency value we calculated earlier, the wavelength is approximately 3.261 × 10^-9 meters or 3.261 nanometers.