Question

The Kₛₚ For AgCl is 2.8x10⁻¹⁰ at a given temperature. The solubility of AgCl in 0.01 molar HCl solution at this temperature will be

A. 2.8 x 10⁻¹² mol L⁻¹
B. 2.8 x 10⁻⁸ mol L⁻¹
C. 5.6 x 10⁻⁸ mol L⁻¹
D.2.8 x 10⁻⁴ mol L⁻¹

Answer 1

The solubility of AgCl in 0.01 molar HCl solution is approximately 5.3x10⁻⁶ mol L⁻¹.

Step-by-step explanation:

The solubility of AgCl in 0.01 molar HCl solution can be determined using the solubility product constant (Ksp). The Ksp for AgCl is given as 2.8x10⁻¹⁰. Let's assume the solubility of AgCl in the HCl solution is x M. At equilibrium, the concentrations of Ag⁺ and Cl⁻ ions are also x M. Therefore, we have [Ag⁺][Cl⁻] = x² = Ksp. Substituting the given Ksp value, we get x² = 2.8x10⁻¹⁰. Solving for x gives us x ≈ 5.3x10⁻⁶ M. Hence, the solubility of AgCl in 0.01 molar HCl solution is approximately 5.3x10⁻⁶ mol L⁻¹.