Final answer:
To solve this problem, we need to represent the tens digit as 'x' and the ones digit as 'x-2'. Then, we can set up an equation to find the value of 'x' and solve it to 86.
Step-by-step explanation:
To solve this problem, let's represent the tens digit as 'x' and the ones digit as 'x-2'. The number formed will be 10x + (x-2). We are given that this number plus its reversed number (which is 10(x-2) + x) is equal to 154. So, we can write the equation as:
10x + (x-2) + 10(x-2) + x = 154
Simplifying the equation, we get:
22x - 22 = 154
Adding 22 to both sides, we get:
22x = 176
Dividing both sides by 22, we find:
x = 8
Therefore, the tens digit is 8 and the ones digit is 6. So, the number is 86.