Question

The reaction: SO₂Cl2(g) →SO2(g) Cl2(g) is a first order reaction. If the initial concentration of SO2Cl2 was 0.0248 mol/L. and the rate constant is 2.2 X 10³/s. What is the concentration of SO₂Cl after 2 hours?

Answer 1

The concentration of SO₂Cl₂ after 2 hours is approximately 0.01076 mol/L.

Step-by-step explanation:

This is a first-order reaction, represented by the reaction equation: SO₂Cl₂(g) →SO₂(g) + Cl₂(g).

In a first-order reaction, the rate of reaction is proportional to the concentration of the reactant raised to the power of 1. The integrated rate law for a first-order reaction is:

ln[SO₂Cl₂] = -kt + ln[SO₂Cl₂]₀, where [SO₂Cl₂] is the concentration at time t, k is the rate constant, and [SO₂Cl₂]₀ is the initial concentration.

To find the concentration of SO₂Cl₂ after 2 hours, we can use the integrated rate law.

Plugging in the values, we have: ln[SO₂Cl₂] = - (2.2 X 10³/s)(2 hours) + ln(0.0248 mol/L).

Solving for [SO₂Cl₂], we find that the concentration of SO₂Cl₂ after 2 hours is approximately 0.01076 mol/L.