Question

A hydraulic turbine has 50 m of head available at a flow rate of 1.30 m³ /s, and its overall turbine–generator efficiency is 78 percent. Determine the electric power output of this turbine.

Answer 1

The electric power output of the hydraulic turbine is 50.7 kW.

Step-by-step explanation:

To determine the electric power output of the hydraulic turbine, we need to use the equation: P = h × Q × η, where P is the power output, h is the head available, Q is the flow rate, and η is the overall turbine–generator efficiency.

Given that the head available is 50 m and the flow rate is 1.30 m³/s, we can plug these values into the equation:

P = 50 m × 1.30 m³/s × 0.78 = 50 × 1.30 × 0.78 = 50.7 kW

Therefore, the electric power output of this turbine is 50.7 kW.