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The length of a rectangular field is four times the width of the field. If you have at most 95 feet of fencing, what is the largest width the field can have and still be enclosed by fencing? Complete the inequality that represents the solution set. Write your answer as a decimal rounded to the tenths place.

a) 9.5
b) 10.0
c) 10.5
d) 11.0

User PeterVC
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1 Answer

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Final answer:

The largest width the field can have and still be enclosed by fencing is 9.5 feet.

Step-by-step explanation:

To find the largest width the field can have and still be enclosed by fencing, we can set up an equation using the information given:

Let's say the width of the field is 'x'.

The length of the field is four times the width, so the length would be 4x.

The perimeter of the rectangular field can be calculated by adding all four sides. In this case, the perimeter is given as 95 feet.

Therefore, the equation becomes:

2x + 2(4x) = 95

Solve for x:

2x + 8x = 95
10x = 95

x = 9.5
The largest width the field can have and still be enclosed by fencing is 9.5 feet, so the answer is 9.5 (option a).

User DoctorPangloss
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