Question

What is the value of x in the equation DE II BC?

a) 0
b) 1
c) 2
d) 3

Answer 1

The value of x in the equation x² + 0.0211x - 0.0211 = 0 is approximately 0.996 or -1.000.

Step-by-step explanation:

The equation given is a quadratic equation, x² + 0.0211x - 0.0211 = 0. To find the value of x, we can use the quadratic formula: x = (-b ± √(b²-4ac))/(2a). In this equation, a = 1, b = 0.0211, and c = -0.0211. Plugging in these values, we get x = (-0.0211 ± √(0.0211² - 4(1)(-0.0211)))/(2(1)). Solving this equation gives us x ≈ 0.996 or x ≈ -1.000.