138k views
5 votes
If system B is capable of lifting 75 lbs with 25 lbs of input force, what is the efficiency of the system?

A. 200%
B. 100%
C. 75%
D. 33.33%

User Rekaszeru
by
8.5k points

1 Answer

3 votes

Final answer:

For system B, the efficiency, calculated by the formula (Output Force / Input Force) × 100%, results in an answer of 300%, which exceeds the possible limit. However, efficiencies over 100% are not realistic due to energy conservation and friction, indicating an issue with either the question or the answer choices provided.

Step-by-step explanation:

The efficiency of a system is calculated by comparing the output force to the input force and is typically expressed as a percentage. For system B, which is able to lift 75 lbs with 25 lbs of input force, efficiency (E) can be calculated using the formula:
E = (Output Force / Input Force) × 100%.

So, for this system:
E = (75 lbs / 25 lbs) × 100% = 3 × 100% = 300%.

However, an efficiency of over 100% is not possible in real-world systems due to the conservation of energy and the inevitable presence of friction and other losses. The efficiency should not exceed 100%, suggesting that there may be an error or misunderstanding in the question. Typically, the maximum efficiency one can achieve is 100%, which occurs only in an ideal, frictionless system. In realistic scenarios, efficiency is always less than 100%.

Given the values provided, choosing among the answer choices, none are factually correct as they do not include an option greater than 100%, but since efficiencies over 100% are not possible, none can truly be accurate. It's possible that the question contains a typo or was otherwise meant to describe a different scenario.

User Junegunn Choi
by
9.2k points