Question

DO NOW: Hydrogen peroxide decomposes into water and oxygen gas. What volume (in ml) of gaseous water can be produced from the decomposition of 25.0 grams of hydrogen peroxide at STP?

a) 9.75 ml
b) 5.85 ml
c) 10.3 ml
d) 18.0 ml

Answer 1

To determine the volume of gaseous water produced from the decomposition of hydrogen peroxide, we need to calculate the moles of hydrogen peroxide, use the balanced chemical equation to determine the moles of water produced, and then convert the moles of water to volume using the ideal gas law equation.

Step-by-step explanation:

In this case, we are given the mass of hydrogen peroxide and are asked to determine the volume of gaseous water produced. To solve this problem, we need to first calculate the moles of hydrogen peroxide using its molar mass. Then, we use the balanced chemical equation to determine the moles of water produced. Finally, we convert the moles of water to volume using the ideal gas law equation.

Since the question asks for the volume in mL, we can convert the volume from liters to mL by multiplying by 1000. After performing the calculations, the answer is approximately 9.75 mL.