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17.5 kJ of energy is used to raise the temperature of 250 g of ethanol. What will the change in temperature be?

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Final answer:

The change in temperature of 250 g of ethanol using 17.5 kJ of energy is approximately 28.69°C, calculated by using the specific heat capacity of ethanol and converting the energy from kJ to J.

Step-by-step explanation:

To calculate the change in temperature of 250 g of ethanol using 17.5 kJ of energy, we'll need to use the specific heat capacity formula: q = mcΔT, where q is the heat energy (in joules), m is the mass (in grams), c is the specific heat capacity (in J/g°C), and ΔT is the change in temperature (in degrees Celsius).

The specific heat capacity of ethanol is approximately 2.44 J/g°C. Therefore, we can rearrange the formula to solve for ΔT: ΔT = q / (mc).

First, we need to convert the energy from kilojoules to joules: 17.5 kJ = 17,500 J.

Now we can calculate the change in temperature:

ΔT = 17,500 J / (250 g × 2.44 J/g°C)

ΔT = 17,500 J / (610 g°C)

ΔT = 28.69°C

So, the change in temperature of the ethanol will be approximately 28.69°C.

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