Question

During their physics field trip to the amusement park, Tyler and Maria took a rider on the Whirligig. The Whirligig ride consists of long swings that spin in a circle at relatively high speeds. As part of their lab, Tyler and Maria estimate that the riders travel through a circle with a radius of 6.11 m and make one turn every 4.85 seconds. Determine the velocity of the riders on the Whirligig. (M/S)

a. 2.51 m/s
b. 3.77 m/s
c. 4.22 m/s
d. 5.09 m/s

Answer 1

The velocity of the riders on the Whirligig ride is approximately 2.51 m/s.

Step-by-step explanation:

The velocity of the riders on the Whirligig ride can be determined using the formula v = 2πr/T, where v is the velocity, r is the radius of the circle, and T is the time taken to complete one revolution. In this case, the radius is 6.11 m and the time is 4.85 seconds. Plugging in these values, we get:

v = (2π * 6.11) / 4.85 ≈ 2.51 m/s

Therefore, the velocity of the riders on the Whirligig ride is approximately 2.51 m/s.