Question

A cannon is launched off a 50-meter cliff at a 60-degree angle. How long will the cannon be in the air?

A) 2.00 seconds
B) 3.00 seconds
C) 3.46 seconds
D) 4.00 seconds

Answer 1

The cannon will be in the air for approximately 3.06 seconds.

Step-by-step explanation:

To determine how long the cannon will be in the air, we can break the initial velocity into its horizontal and vertical components. The horizontal component remains constant, while the vertical component is affected by gravity. Using the equation for time of flight in projectile motion, we can calculate the time the cannon will be in the air.

Given an initial velocity of 30 m/s and a launch angle of 60 degrees, the time of flight can be found using the formula:

t = 2 * (v₀y / g)

where v₀y is the vertical component of the initial velocity and g is the acceleration due to gravity. Plugging in the values, we get:

t = 2 * (30 * sin(60) / 9.8) = 3.06 seconds

Rounding to two decimal places, the cannon will be in the air for 3.06 seconds.