Question

When 2.50 g of glucose (C₆H₁₂O₆) burns in air, carbon dioxide gas and liquid water are formed. 38.9 kJ of heat are also liberated. What is the heat flow of the reaction if 95.0 g of glucose are burned? The reaction takes place in a bomb calorimeter where 4.50 g of glucose are burned. What is the heat capacity of the bomb if the temperature of the water in the bomb increases from 22.75 °C to 26.25 °C?

Answer 1

The heat flow of the reaction when 95.0 g of glucose are burned is 1.47 kJ. The heat capacity of the bomb is 0.37 kJ/°C.

Step-by-step explanation:

In order to determine the heat flow of the reaction when 95.0 g of glucose are burned, we can use the concept of proportionality.

First, we calculate the heat flow for 2.50 g of glucose burned using the given heat value of 38.9 kJ. Using this information, we can set up a proportion:

(38.9 kJ)/(2.50 g) = x/(95.0 g)

Solving for x, we find that the heat flow for 95.0 g of glucose burned is 1.47 kJ.

To determine the heat capacity of the bomb, we need to use the formula:

Heat flow = Heat capacity x Temperature change

Substituting the given values, we have:

1.47 kJ = Heat capacity x (26.25 °C - 22.75 °C)

Solving for the heat capacity, we find it to be 0.37 kJ/°C.