Question

Write the equation -4x^2 + 9y^2 + 32x + 36y - 64 = 0 in standard form.

a) -4x^2 + 9y^2 + 32x + 36y - 64 = 0
b) 9y^2 - 4x^2 + 36y + 32x = 64
c) 9y^2 - 4x^2 + 32x + 36y = 64
d) -4x^2 + 9y^2 + 36y + 32x = 64

Answer 1

The correct standard form of the equation is 9y^2 - 4x^2 + 36y + 32x = 64.

Step-by-step explanation:

To write the equation -4x^2 + 9y^2 + 32x + 36y - 64 = 0 in standard form, we need to transpose the constant term to the other side of the equation while keeping the other terms on one side.

The result would rearrange the terms to group the x's and y's together and then follow by the constant term on the opposite side of the equals sign. Therefore, the correct standard form of the given equation is 9y^2 - 4x^2 + 36y + 32x = 64, which corresponds to option c).