148k views
4 votes
Describe the transition from f(x) = x^3 to g(x) = 3(x-2)^3 - 8. What is the end behavior?

a) The transition is linear.
b) The transition is exponential.
c) The end behavior is decreasing.
d) The end behavior is increasing

User DeadChex
by
7.9k points

1 Answer

3 votes

Final answer:

The transition from f(x) to g(x) involves a horizontal shift, a vertical stretch, and a downward translation, but the cubic end behavior remains the same: decreasing as x approaches negative infinity and increasing as x approaches positive infinity.

Step-by-step explanation:

The transition from f(x) = x^3 to g(x) = 3(x-2)^3 - 8 consists of several transformations. The function is first translated horizontally 2 units to the right to get (x-2)^3. Then, it is vertically stretched by a factor of 3, and finally, it is translated 8 units downward. These transformations neither change the end behavior of the function nor its overall cubic shape, which means the end behavior remains the same as the parent function f(x) = x^3.

For the cubic function f(x) = x^3, as x goes to negative infinity, the function decreases without bound, and as x goes to positive infinity, the function increases without bound. The transformed function g(x) = 3(x-2)^3 - 8 maintains this behavior. Hence, the end behavior of g(x) is: as x approaches negative infinity, g(x) decreases without bound (c), and as x approaches positive infinity, g(x) increases without bound (d).

User Brennen
by
7.4k points