Question

What is an equation, in point-slope form, of the line that passes through the point (4,-1) and has a slope 6? (Rubric A: 2)

a) y + 1 = 6(x - 4)
b) y - 1 = 6(x - 4)
c) y - 1 = -5x + 4
d) y - 1 = -6(x + 4)

Answer 1

The equation, in point-slope form, for the line passing through the point (4,-1) with a slope of 6 is y + 1 = 6(x - 4).

Step-by-step explanation:

The equation, in point-slope form, of a line is given by y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

In this case, the given point is (4,-1) and the slope is 6. Plugging these values into the equation, we get:

y - (-1) = 6(x - 4)

Simplifying, we get:

y + 1 = 6(x - 4)

Therefore, the correct equation, in point-slope form, is y + 1 = 6(x - 4), which corresponds to option a).