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If 6.890 moles of neon gas is at 10 degrees C and has a pressure of 2.800 atm, then what is the volume?

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Final answer:

To find the volume of the neon gas at a given temperature and pressure, we can use the ideal gas law equation PV = nRT. By plugging in the given values, we can calculate the volume to be 59.1 L.

Step-by-step explanation:

To find the volume of the neon gas, we can use the ideal gas law equation, PV = nRT. In this equation, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. We need to convert the temperature from degrees Celsius to Kelvin by adding 273.15. The ideal gas constant R is 0.0821 L.atm/mol.K. Plugging in the given values:

P = 2.800 atm

n = 6.890 mol

T = 10 + 273.15 = 283.15 K

Using the equation, we can solve for V:

V = (n * R * T) / P = (6.890 mol * 0.0821 L.atm/mol.K * 283.15 K) / 2.800 atm = 59.1 L

The volume of the neon gas is 59.1 L.

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