Final answer:
A man with genotype IA i and a woman with genotype IB i can have children with genotypes IAIB (type AB), IA i (type A), IB i (type B), and ii (type O). The ABO blood group system depicts about codominance and multiple alleles. Also, the woman can donate blood to the man, but not vice versa.
Step-by-step explanation:
The question relates to the ABO blood group system in humans, which involves the IA, IB, and i alleles. These alleles determine an individual's blood type: IA for type A, IB for type B, and i for type O, with IA and IB being codominant and both dominant over i. A man with blood type IA i (which means he is heterozygous for type A) and a woman with blood type IB i (which means she is heterozygous for type B) can have children with the following probable genotypes: IAIB (type AB), IA i (type A), IB i (type B), and ii (type O).
Their offspring's possible phenotypes for the ABO blood group would include type A, type B, type AB, and type O. This is due to the codominance of the IA and IB alleles, where both A and B antigens can be expressed together in type AB individuals, as well as the presence of the recessive allele i. Consequently, when a heterozygous type A is crossed with a heterozygous type B, the offspring's genotype ratio will be 1 IAIB (type AB): 1 IA i (type A): 1 IB i (type B): 1 ii (type O).
As for the question of blood donation, the woman with blood type IB i can donate blood to her husband with type IA i because both AB and B blood types are compatible with type A, but the husband with type A blood cannot donate to the wife since type A blood is not compatible with type B or AB (due to the presence of A antigens, which would be foreign to B or AB blood).