Question

What is the value of H, K, and R in this Equation Of a Circle (x-5)^2 + (y+3)^2 = 36?

a) H = 5, K = -3, R = 6
b) H = -5, K = 3, R = 36
c) H = -3, K = 5, R = 6
d) H = 3, K = -5, R = 36

Answer 1

The value of H is 5, K is -3, and R is 6 in the given equation of a circle, corresponding to option a).

Step-by-step explanation:

The equation of a circle in standard form is (x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center of the circle and r is the radius. Comparing the given equation (x - 5)^2 + (y + 3)^2 = 36 with the standard form, we can see that h = 5, k = -3, and r = 6 (since the radius is the square root of the right-hand side of the equation, and √36 = 6). Therefore, the value of H is 5, K is -3, and R is 6, which corresponds to option a).