Question

Carbon steel has a specific heat of 0.49 J/gºC. If a 7.0 g piece of carbon steel increases in temperature from 10°C to 21°C, then how much heat was absorbed by the carbon steel?

a) Step 1: Identify the variables
b) Step 2: Replace the letters w/ numbers and calculate
c) q = 31.5 J
d) q = 31.5 kJ

Answer 1

To calculate the heat absorbed by carbon steel, we use the formula q = mc∆T. The heat absorbed is 37.59 J as the piece of carbon steel increased in temperature from 10°C to 21°C.

Step-by-step explanation:

To answer the question on how much heat was absorbed by the carbon steel as it increased in temperature from 10°C to 21°C, we follow these steps:

• Specific heat (c) = 0.49 J/g°C
• Mass (m) = 7.0 g
• Change in temperature (∆T) = Final temperature - Initial temperature = 21°C - 10°C = 11°C

The formula for calculating heat absorbed or released is:

q = mc∆T

Replacing letters with numbers we get:

q = (7.0 g) × (0.49 J/g°C) × (11°C)

q = 37.59 J

The heat absorbed (q) by the carbon steel is 37.59 J, so none of the provided options are correct.