Question

The sled is being pulled up a hill with a force of 73 N at a 39° angle. If the coefficient of friction is 0.15 and the mass is 10 kg, what is the force of friction on the sled?

Answer 1

The force of friction on the sled is approximately 14.3 N.

Step-by-step explanation:

The force of friction on the sled can be calculated using the formula:

Force of friction = coefficient of friction * normal force

To find the normal force, we need to consider the forces acting on the sled. The vertical component of the applied force is counteracted by the weight of the sled. The normal force can be calculated as:

Normal force = mass * gravitational acceleration * cos(theta)

Substituting the given values into the formula:

Normal force = 10 kg * 9.8 m/s^2 * cos(39°)

Next, we can substitute the normal force and the coefficient of friction into the formula to find the force of friction:

Force of friction = 0.15 * (10 kg * 9.8 m/s^2 * cos(39°))

Calculating the expression:

Force of friction ~ 14.3 N