Question

A weather balloon has a volume of 52.5 liters at a temperature of 295 K. The balloon is released and rises to an altitude where the temperature is 252 K. The original pressure of the given weather balloon at 295 K is 45.6 kPa. The pressure at the higher altitude when the temperature is 252K is 55 kPa. Assume the balloon does not burst. Show a correct numerical setup for calculating the new volume.

Answer 1

To determine the new volume of the weather balloon at a higher altitude, you can use the combined gas law equation, rearranging it to solve for the new volume based on the given initial and final conditions of temperature and pressure.

Step-by-step explanation:

The question involves finding the new volume of a weather balloon after a change in temperature and pressure at a higher altitude. To do this, we can use the combined gas law which relates pressure (P), volume (V), and temperature (T). The combined gas law is given by: PV/T = constant. Given the initial conditions of the balloon are 52.5 liters at 295 K and 45.6 kPa, and the final conditions are temperature at 252 K and pressure at 55 kPa, we can set up the equation as follows:

(45.6 kPa * 52.5 L) / 295 K = (55 kPa * V2) / 252 K

To find the new volume, V2, you would solve the equation for V2.