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Find the missing number (n) in each problem:

a. n = 5/7
b. n = 1/4
c. n = -3/5
d. n = -1/3
e. n = 32/48
f. n = 3/2

User CeamKrier
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1 Answer

5 votes

Final answer:

The student has provided a series of numerical values or fractions for the variable 'n'. There is no actual problem to solve; the values assigned to 'n' are already presented. The only simplification necessary is for 'e', where 'n' equals 32/48, which when simplified becomes 2/3.

Step-by-step explanation:

The student's question involves calculation of missing numbers represented by the variable n in various fractions or numbers. It seems that n in each problem simply represents the numerical value already given, meaning there is no missing value to find. Let's review each:


  • a. n = 5/7 - Here, n is the fraction 5/7.

  • b. n = 1/4 - For this item, n is the fraction 1/4.

  • c. n = -3/5 - n is -3/5, indicating a negative fraction.

  • d. n = -1/3 - This is another negative fraction, with n being -1/3.

  • e. n = 32/48 - If we simplify this fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 16, we get 2/3. So, the simplified value of n is 2/3.

  • f. n = 3/2 - Here, n is an improper fraction, equal to 1.5 in decimal form.

User CamiloEr
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