Final answer:
The distance between points II (6,2) and JJ (6,-4) is found by the difference in y-coordinates, resulting in a distance of 6 units.
Step-by-step explanation:
To find the distance between two points in a Cartesian plane, we use the distance formula, which is derived from the Pythagorean theorem. In this case, the points are II (6,2) and JJ (6,-4). Since the x-coordinates are the same, these points lie on a vertical line and we can calculate the distance by taking the difference of the y-coordinates.
Distance = |y2 - y1| = |(-4) - (2)| = |-6| = 6 units
The correct answer is therefore D) 6 units, which is the vertical separation between the points II and JJ.