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The coordinates of point II are (6,2) and the coordinates of point JJ are (6,-4). What is the distance, in units, between point II and point JJ?

A) 0 units
B) 2 units
C) 4 units
D) 6 units

User Kodartcha
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7.6k points

1 Answer

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Final answer:

The distance between points II (6,2) and JJ (6,-4) is found by the difference in y-coordinates, resulting in a distance of 6 units.

Step-by-step explanation:

To find the distance between two points in a Cartesian plane, we use the distance formula, which is derived from the Pythagorean theorem. In this case, the points are II (6,2) and JJ (6,-4). Since the x-coordinates are the same, these points lie on a vertical line and we can calculate the distance by taking the difference of the y-coordinates.

Distance = |y2 - y1| = |(-4) - (2)| = |-6| = 6 units

The correct answer is therefore D) 6 units, which is the vertical separation between the points II and JJ.

User Rishi Dwivedi
by
8.5k points
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