Question

Write the equation -4x^2 + 9y^2 + 32x + 36y - 64 = 0 in standard form. Show each step of the process.

A. 4x^2 + 9y^2 + 32x + 36y - 64 = 0
B. 4x^2 - 9y^2 + 32x + 36y - 64 = 0
C. 4x^2 + 9y^2 - 32x - 36y + 64 = 0
D. 4x^2 - 9y^2 - 32x - 36y + 64 = 0

Answer 1

To write the equation -4x^2 + 9y^2 + 32x + 36y - 64 = 0 in standard form, rearrange the terms to group the x and y terms and move the constant to the other side of the equation. The correct equation in standard form is 4x^2 - 9y^2 + 32x + 36y - 64 = 0.

Step-by-step explanation:

To write the equation -4x^2 + 9y^2 + 32x + 36y - 64 = 0 in standard form, we need to rearrange the terms so that the x^2 and y^2 terms are positive and all constants are on one side of the equation.

To do this, we can group the x terms together, the y terms together, and move the constant to the other side of the equation.

The correct equation in standard form is: 4x^2 - 9y^2 + 32x + 36y - 64 = 0.