Question

The width of a rectangle is 52 centimeters. The perimeter is at least 734. Write and solve an inequality to find the possible lengths of the rectangle.

A. 2x + 2(52) ≥ 734; x ≤ 315
B. 2x + 2(52) ≤ 734; x ≥ 315
C. 2x + 2(52) ≥ 734; x ≥ 315
D. 2x + 2(52) ≤ 734; x ≤ 315

Answer 1

To find the possible lengths of the rectangle, we can use the formula for the perimeter of a rectangle: P = 2L + 2W, where P is the perimeter, L is the length, and W is the width. In this case, the width is 52 centimeters and the perimeter is at least 734 centimeters. Using this information, we can write and solve an inequality to find the possible lengths of the rectangle.

Step-by-step explanation:

To find the possible lengths of the rectangle, we can use the formula for the perimeter of a rectangle: P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.

In this case, we know that the width is 52 centimeters and the perimeter is at least 734 centimeters.

So we can write the inequality as: 2L + 2(52) ≥ 734. Solving this inequality, we get: L ≥ 315.

Therefore, the possible lengths of the rectangle are greater than or equal to 315 centimeters.

The correct answer is option C. 2x + 2(52) ≥ 734; x ≥ 315.