Question

An urn contains 8 balls identical in every way except color. There are 2 red balls, 5 green balls, and 1 blue ball. You draw 2 balls (one at a time) from the urn and replace the first before drawing the second. Find the probability that the first ball is red AND the second is green.

a) 1/8
b) 2/8
c) 10/64
d) 5/32

Answer 1

The probability of drawing a red ball and then a green ball from the urn with replacement is 10/64.

Step-by-step explanation:

To find the probability that the first ball is red AND the second is green, we need to determine the probability of drawing a red ball on the first draw and a green ball on the second draw with replacement.

There are 2 red balls out of a total of 8 balls, so the probability of drawing a red ball on the first draw is 2/8.

Since the first ball is replaced before the second draw, the probability of drawing a green ball on the second draw is also 5/8.

To find the probability of both events occurring, we multiply the probabilities: (2/8) * (5/8) = 10/64.

Therefore, the correct answer is c) 10/64.