Question

Solve the quadratic equation below. (1 Point each)

X^2 + 8 = 4
A. X = 2
B. X = -2
C. X = 4
D. X = -4

2X^2 + 31 = 9
A. X = 3
B. X = -3
C. X = 4
D. X = -4

Answer 1

To solve the given quadratic equations, one can use the quadratic formula. However, both equations result in the square root of a negative number, indicating no real solutions.

Step-by-step explanation:

To solve quadratic equations, you can use the quadratic formula, which is x = ∛(b² - 4ac)/2a, where a, b, and c are the coefficients in the standard form equation ax²+bx+c = 0.

Let's solve the equations given by applying the above technique:

1. For the equation X² + 8 = 4, first rearrange it to conform to the standard form: X² + 4 = 0. This can be rewritten as X² = -4, and since there's no real number square that equals a negative number, this equation has no real solution.
2. For the second equation, 2X² + 31 = 9, again rearrange to standard form: 2X² + 22 = 0. Next, apply the quadratic formula, where a = 2, b = 0, and c = 22. Since ∛(b² - 4ac) would be the square root of a negative number, this equation also has no real solution.

Therefore, neither equation A nor equation B has solutions among the provided options.