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At time t=0 a cart is at x=10 m and has a velocity of 6 m/s in the negative x direction. The cart has a constant acceleration of 3 m/s^2 in the positive x-direction. What is the velocity of the cart at t=3s?

a. 9 m/s
b. 15 m/s
c. -3 m/s
d. 12 m/s

User JoeSmith
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1 Answer

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Final answer:

The velocity of the cart at t=3 seconds is calculated using the kinematic equation for velocity, yielding a result of 3 m/s in the positive x-direction.

Step-by-step explanation:

The question involves finding the velocity of a cart at a certain time given its initial position, velocity, and constant acceleration. To find the velocity of the cart at t=3 seconds (t=3s), we can use the kinematic equation for velocity:

v = v0 + at,

where v is the final velocity, v0 is the initial velocity, a is the constant acceleration, and t is the time.

Here, the initial velocity v0 = -6 m/s (since it's in the negative x-direction), the acceleration a = 3 m/s2 (in the positive x-direction), and the time t = 3 s.

Substituting the values into the equation:

v = (-6 m/s) + (3 m/s2)(3 s) = -6 m/s + 9 m/s = 3 m/s.

The velocity of the cart at t=3s is 3 m/s in the positive x-direction.

User Reza Keshavarz
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