Final answer:
The weight of the student is 490 N. The combined weight of the student and the table is 1100 N. Therefore, the total normal force on the table by the floor is 1100 N.
Step-by-step explanation:
The weight of a student with a mass of 50 kg can be calculated using the formula W = m × g, where W is weight, m is mass, and g is the acceleration due to gravity (approximately 9.8 m/s²). So the weight of the student would be 50 kg × 9.8 m/s² = 490 N (newtons). The weight of the student and the table combined is then 490 N + 600 N = 1090 N, which gets rounded up to 1100 N due to significant figures in practical problems.
The total normal force on the table by the floor would be the combined weight of the student and the table, which we've already calculated as 1100 N. Thus, the correct answer is c. 1100 N.