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If m∠DCF = 8x + 30 and m∠ECF = 6x - 5, find m∠DCE.

a. 8x + 30 - (6x - 5)
b. 8x + 30 + (6x - 5)
c. 8x + 30 × (6x - 5)
d. 8x + 30 ÷ (6x - 5)

1 Answer

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To find m∠DCE, use the properties of angles in a triangle and the given angles m∠DCF and m∠ECF. The equation is 14x + 25 + m∠DCE = 180°.

To find m∠DCE, we need to use the properties of angles in a triangle. In triangle DCF, the sum of the interior angles is 180°. So, m∠DCF + m∠ECF + m∠DCE = 180°. Substituting the given values, we have (8x + 30) + (6x - 5) + m∠DCE = 180°. Simplifying the equation, we get 14x + 25 + m∠DCE = 180°. Rearranging the terms, we find m∠DCE = 180° - 14x - 25.

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