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If w=2, x=6, y=4, and z=3, what is the value of 2w²+8x÷3y−4z?

a) 8
b) 2
c) 4
d) 0

1 Answer

4 votes

Final answer:

The value of 2w²+8x÷3y−4z is 0.

Step-by-step explanation:

To find the value of 2w²+8x÷3y−4z with the given values of w=2, x=6, y=4, and z=3, we substitute these values into the expression:

2w²+8x÷3y−4z = 2(2)²+8(6)÷3(4)−4(3)

Simplifying, we get:

2(4)+48÷12−12

8+4−12

= 0

Therefore, the value of 2w²+8x÷3y−4z when w=2, x=6, y=4, and z=3 is 0.

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