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What is the end behavior of the graph of the function f(x) = -0.33x^2 + 8x - 11?

A) As x increases, f(x) increases; as x decreases, f(x) decreases.
B) As x increases, f(x) decreases; as x decreases, f(x) decreases.
C) As x increases, f(x) increases; as x decreases, f(x) increases.
D) As x increases, f(x) decreases; as x decreases, f(x) increases.

User ScottMcG
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1 Answer

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Final answer:

The end behavior of the function f(x) = -0.33x^2 + 8x - 11 is such that as x increases or decreases, f(x) decreases, which corresponds to option B.

Step-by-step explanation:

The end behavior of the graph of the function f(x) = -0.33x^2 + 8x - 11 can be determined by looking at the leading coefficient and the power of x in the highest degree term. Since the highest degree term is x^2 and the leading coefficient is negative (-0.33), this tells us that the graph opens downwards, and thus both ends will point down as x becomes very large or very small (i.e., as x approaches positive or negative infinity).

Therefore, as x increases without bound (x → ∞), the value of f(x) will decrease without bound due to the negative coefficient. Similarly, as x decreases without bound (x → -∞), f(x) will also decrease without bound. This means the correct answer is:

B) As x increases, f(x) decreases; as x decreases, f(x) decreases.

User Plockc
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