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Contrast the following electron transitions in terms of energy (absorb/release and higher/lower).

A.N=1 to N=5
B.N=5 to N=3
C.N=3 to N=5
D.N=5 to N=1
a) A absorbs energy and goes to a higher energy state.
b) B releases energy and goes to a lower energy state.
c) C absorbs energy and goes to a higher energy state.
d) D releases energy and goes to a lower energy state.

1 Answer

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Final answer:

In electron transitions, absorption of energy leads to higher energy states, while release of energy leads to lower energy states.

Step-by-step explanation:

In electron transitions, the absorption or emission of radiation involves a change in energy levels. When an electron transitions from a lower energy level to a higher energy level, it absorbs energy and is said to be in an excited state (e.g., A absorbs energy and goes to a higher energy state, N=1 to N=5). On the other hand, when an electron transitions from a higher energy level to a lower energy level, it releases energy and returns to a lower energy state (e.g., B releases energy and goes to a lower energy state, N=5 to N=3).

The same concept applies to C and D. In C, the transition from N=3 to N=5 involves the absorption of energy, taking the electron to a higher energy state. In D, the transition from N=5 to N=1 involves the release of energy, bringing the electron to a lower energy state.

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