Final answer:
To find the height reached by an object launched into the air, we can use the equation h = (v^2 * sin^2θ) / (2g), where h is the height, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity. Using the given initial velocity of 61.5 m/s and assuming a launch angle of 90 degrees, the height is calculated to be 150.625 meters.
Step-by-step explanation:
To determine how high the object goes when launched into the air, we can use the principles of projectile motion. In this case, the object is launched with an initial velocity of 61.5 m/s. Assuming no air resistance, the height can be found using the equation h = (v^2 * sin^2θ) / (2g), where h is the height, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.
Since the angle of launch is not given, we can assume it is launched vertically upward. In this case, the launch angle (θ) would be 90 degrees. Plugging in the values into the equation, we get h = (61.5^2 * sin^2(90)) / (2 * 9.8). Evaluating the expression gives us a height of 150.625 meters.
Therefore, the correct answer is A. 150.625 meters.