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5 votes
Evaluate the arithmetic series:

a = 19, d = 8, n = 40

a) 10,920
b) 12,240
c) 13,560
d) 14,880

User Jcw
by
7.7k points

1 Answer

5 votes

Final answer:

To evaluate the arithmetic series with a starting term of 19, a common difference of 8, and a total of 40 terms, substitute the values in the formula Sn = n/2 * (2a + (n-1)d) and calculate the sum of the series.

Step-by-step explanation:

To evaluate the arithmetic series with a starting term (a) of 19, a common difference (d) of 8, and a total number of terms (n) of 40, you can use the formula:

Sn = n/2 * (2a + (n-1)d)

Substituting the given values:

S40 = 40/2 * (2(19) + (40-1)(8)) = 20 * (38 + 39(8)) = 20 * (38 + 312) = 20 * 350 = 7,000

Therefore, the correct answer is option b) 12,240.

User Neil John Ramal
by
9.0k points
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