Question

In the given linear equation (3−k)x−4(3−k)y=−27, when graphed in the xy-plane, what is the slope of the line?

Answer 1

The slope of the line in the given linear equation is (3-k).

Step-by-step explanation:

The given linear equation is (3-k)x - 4(3-k)y = -27.

To find the slope of the line, we need to rewrite the equation in the form y = mx + b, where m is the slope.

Rewriting the equation, we have:

(3-k)x - 4(3-k)y = -27 => (3-k)x + 4(3-k)y = 27 => (3-k)x + 12(3-k)y = 27 => (3-k)(x + 12y) = 27.

Since the equation is in the form (3-k)(x + 12y) = 27, we can see that the slope of the line is (3-k).