Question

Jacob rode on his bike straight down a hill, accelerating from a speed of 3 m/s to 9 m/s in a total time of 4 s. What was his acceleration? [a = Δv/t]

A. 3 m/s²
B. 1.5 m/s²
C. 2.25 m/s²
D. 0.75 m/s²

Answer 1

The acceleration of Jacob's bike as it accelerated down the hill from 3 m/s to 9 m/s over 4 seconds is 1.5 m/s².

Step-by-step explanation:

The student's question is asking about the acceleration of a bicycle as it went down a hill. Given that the bike's speed changed from 3 m/s to 9 m/s over a period of 4 seconds, we can calculate acceleration using the formula a = Δv/t, where 'a' is the acceleration, 'Δv' is the change in velocity, and 't' is the time over which the change occurred. The change in velocity (Δv) is the final velocity (9 m/s) minus the initial velocity (3 m/s), which equals 6 m/s. The time (t) is 4 seconds. Therefore, the acceleration (a) is 6 m/s divided by 4 s, which equals 1.5 m/s².