Question

ABCD is a parallelogram.

AD = 12 cm.
DC = 9 cm.
The perpendicular distance of
from CD is 8 cm.
What is the perpendicular distance of AD from BC?

Answer 1

9514 1404 393

Answer:

6 cm

Explanation:

The area of the parallelogram is the same, either way you figure it.

A = bh

A = CD(length ⊥ to CD)

A = (9 cm)(8 cm) = 72 cm²

__

A = AD(length ⊥ AD)

72 cm² = (12 cm)(length ⊥ AD)

(length ⊥ AD) = (72 cm²)/(12 cm) = 6 cm

The perpendicular distance of AD from BC is 6 cm.