Final answer:
The tension in the cable supporting the elevator is 2040 N during acceleration and constant velocity, and -1020 N during deceleration. Additional information is needed to calculate the height and final velocity of the elevator.
Step-by-step explanation:
In order to determine the tension in the cable supporting the elevator, we need to consider the mass of the elevator and the acceleration it experiences. According to the information given, the elevator is filled with passengers and has a mass of 1700 kg. The elevator accelerates upward at a rate of 1.20 m/s² for 1.50 s. Using Newton's second law, we can calculate the tension in the cable:
Tension = mass × acceleration = 1700 kg × 1.20 m/s² = 2040 N
Therefore, the tension in the cable supporting the elevator during acceleration is 2040 N.
During constant velocity, the elevator experiences zero net acceleration. This means that the tension in the cable remains the same as during acceleration. So, the tension in the cable during the constant velocity phase is also 2040 N.
During deceleration, the elevator experiences negative acceleration. Given that the elevator decelerates at a rate of 0.600 m/s² for 3.00 s, we can calculate the tension in the cable:
Tension = mass × acceleration = 1700 kg × (-0.600 m/s²) = -1020 N
Therefore, the tension in the cable supporting the elevator during deceleration is -1020 N (negative value indicates the direction of the force).
To calculate the height the elevator has moved above its original starting point and its final velocity, we need additional information such as the initial velocity and the displacement of the elevator during each phase.