Answer:
3x + 2y = -4
Explanation:
x intercept of the line occurs at y = 0
Given the equation 3x+2y = 6
3x+2(0) = 6
3x = 6
x = 2
The x intercept is at (2, 0)
Adding -2 to each axis will give (2-2, 0-2) = (0, -2)
y intercept of the line occurs at x = 0
Given the equation 3x+2y = 6
3(0)+2y = 6
2y = 6
y =3
The x intercept is at (0, 3)
Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)
The new coordinates are (0, -2 and (-2, 1)
Using the point slope form of the equation y - y0 = m(x-x0)
slope m = y2-y1/x2-x1
m = 1-(-2)/-2-0
m = 1+2/-2
m = -3/2
Using m = -3/2 and (0, -2)
y - (-2) = -3/2(x-0)
y+2 = -3/2 x
2(y+2) = -3x
2y+4 = -3x
-3x-2y = 4
3x + 2y = -4
Hence the required equation is 3x + 2y = -4