Question

By solving the equation 2n^2 + 4n - 16 = 0, solutions are:

a) {-4, 2}
b) {-2, 4}
c) {-16}
d) {-4}

Answer 1

The solutions to the given quadratic equation are x = -4 and x = 2.

Step-by-step explanation:

The given equation is a quadratic equation of the form at² + bt + c = 0, where a = 2, b = 4, and c = -16. Its solutions can be found using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values, we get:

x = (-4 ± √(4² - 4(2)(-16))) / (2(2))

Simplifying further gives us:

x = (-4 ± √(16 + 128)) / 4

x = (-4 ± √144) / 4

x = (-4 ± 12) / 4

Therefore, the solutions to the equation are x = -4 and x = 2.